Optimal. Leaf size=96 \[ \frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)+\frac {a^3 x^8}{72}+\frac {4 x^2}{315 a^3}-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {4 \log \left (1-a^2 x^2\right )}{315 a^5}-\frac {11 a x^6}{378}+\frac {1}{5} x^5 \tanh ^{-1}(a x)+\frac {2 x^4}{315 a} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.19, antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 4, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6012, 5916, 266, 43} \[ \frac {a^3 x^8}{72}+\frac {4 x^2}{315 a^3}+\frac {4 \log \left (1-a^2 x^2\right )}{315 a^5}+\frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)-\frac {11 a x^6}{378}+\frac {2 x^4}{315 a}+\frac {1}{5} x^5 \tanh ^{-1}(a x) \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 43
Rule 266
Rule 5916
Rule 6012
Rubi steps
\begin {align*} \int x^4 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x) \, dx &=\int \left (x^4 \tanh ^{-1}(a x)-2 a^2 x^6 \tanh ^{-1}(a x)+a^4 x^8 \tanh ^{-1}(a x)\right ) \, dx\\ &=-\left (\left (2 a^2\right ) \int x^6 \tanh ^{-1}(a x) \, dx\right )+a^4 \int x^8 \tanh ^{-1}(a x) \, dx+\int x^4 \tanh ^{-1}(a x) \, dx\\ &=\frac {1}{5} x^5 \tanh ^{-1}(a x)-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)-\frac {1}{5} a \int \frac {x^5}{1-a^2 x^2} \, dx+\frac {1}{7} \left (2 a^3\right ) \int \frac {x^7}{1-a^2 x^2} \, dx-\frac {1}{9} a^5 \int \frac {x^9}{1-a^2 x^2} \, dx\\ &=\frac {1}{5} x^5 \tanh ^{-1}(a x)-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)-\frac {1}{10} a \operatorname {Subst}\left (\int \frac {x^2}{1-a^2 x} \, dx,x,x^2\right )+\frac {1}{7} a^3 \operatorname {Subst}\left (\int \frac {x^3}{1-a^2 x} \, dx,x,x^2\right )-\frac {1}{18} a^5 \operatorname {Subst}\left (\int \frac {x^4}{1-a^2 x} \, dx,x,x^2\right )\\ &=\frac {1}{5} x^5 \tanh ^{-1}(a x)-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)-\frac {1}{10} a \operatorname {Subst}\left (\int \left (-\frac {1}{a^4}-\frac {x}{a^2}-\frac {1}{a^4 \left (-1+a^2 x\right )}\right ) \, dx,x,x^2\right )+\frac {1}{7} a^3 \operatorname {Subst}\left (\int \left (-\frac {1}{a^6}-\frac {x}{a^4}-\frac {x^2}{a^2}-\frac {1}{a^6 \left (-1+a^2 x\right )}\right ) \, dx,x,x^2\right )-\frac {1}{18} a^5 \operatorname {Subst}\left (\int \left (-\frac {1}{a^8}-\frac {x}{a^6}-\frac {x^2}{a^4}-\frac {x^3}{a^2}-\frac {1}{a^8 \left (-1+a^2 x\right )}\right ) \, dx,x,x^2\right )\\ &=\frac {4 x^2}{315 a^3}+\frac {2 x^4}{315 a}-\frac {11 a x^6}{378}+\frac {a^3 x^8}{72}+\frac {1}{5} x^5 \tanh ^{-1}(a x)-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)+\frac {4 \log \left (1-a^2 x^2\right )}{315 a^5}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.03, size = 96, normalized size = 1.00 \[ \frac {1}{9} a^4 x^9 \tanh ^{-1}(a x)+\frac {a^3 x^8}{72}+\frac {4 x^2}{315 a^3}-\frac {2}{7} a^2 x^7 \tanh ^{-1}(a x)+\frac {4 \log \left (1-a^2 x^2\right )}{315 a^5}-\frac {11 a x^6}{378}+\frac {1}{5} x^5 \tanh ^{-1}(a x)+\frac {2 x^4}{315 a} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.56, size = 92, normalized size = 0.96 \[ \frac {105 \, a^{8} x^{8} - 220 \, a^{6} x^{6} + 48 \, a^{4} x^{4} + 96 \, a^{2} x^{2} + 12 \, {\left (35 \, a^{9} x^{9} - 90 \, a^{7} x^{7} + 63 \, a^{5} x^{5}\right )} \log \left (-\frac {a x + 1}{a x - 1}\right ) + 96 \, \log \left (a^{2} x^{2} - 1\right )}{7560 \, a^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [B] time = 0.20, size = 383, normalized size = 3.99 \[ \frac {4}{945} \, a {\left (\frac {6 \, \log \left (\frac {{\left | -a x - 1 \right |}}{{\left | a x - 1 \right |}}\right )}{a^{6}} - \frac {6 \, \log \left ({\left | -\frac {a x + 1}{a x - 1} + 1 \right |}\right )}{a^{6}} - \frac {\frac {6 \, {\left (a x + 1\right )}^{7}}{{\left (a x - 1\right )}^{7}} - \frac {45 \, {\left (a x + 1\right )}^{6}}{{\left (a x - 1\right )}^{6}} - \frac {274 \, {\left (a x + 1\right )}^{5}}{{\left (a x - 1\right )}^{5}} - \frac {214 \, {\left (a x + 1\right )}^{4}}{{\left (a x - 1\right )}^{4}} - \frac {274 \, {\left (a x + 1\right )}^{3}}{{\left (a x - 1\right )}^{3}} - \frac {45 \, {\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2}} + \frac {6 \, {\left (a x + 1\right )}}{a x - 1}}{a^{6} {\left (\frac {a x + 1}{a x - 1} - 1\right )}^{8}} + \frac {6 \, {\left (\frac {210 \, {\left (a x + 1\right )}^{6}}{{\left (a x - 1\right )}^{6}} + \frac {315 \, {\left (a x + 1\right )}^{5}}{{\left (a x - 1\right )}^{5}} + \frac {441 \, {\left (a x + 1\right )}^{4}}{{\left (a x - 1\right )}^{4}} + \frac {126 \, {\left (a x + 1\right )}^{3}}{{\left (a x - 1\right )}^{3}} + \frac {36 \, {\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2}} - \frac {9 \, {\left (a x + 1\right )}}{a x - 1} + 1\right )} \log \left (-\frac {\frac {a {\left (\frac {a x + 1}{a x - 1} + 1\right )}}{\frac {{\left (a x + 1\right )} a}{a x - 1} - a} + 1}{\frac {a {\left (\frac {a x + 1}{a x - 1} + 1\right )}}{\frac {{\left (a x + 1\right )} a}{a x - 1} - a} - 1}\right )}{a^{6} {\left (\frac {a x + 1}{a x - 1} - 1\right )}^{9}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [A] time = 0.03, size = 87, normalized size = 0.91 \[ \frac {a^{4} x^{9} \arctanh \left (a x \right )}{9}-\frac {2 a^{2} x^{7} \arctanh \left (a x \right )}{7}+\frac {x^{5} \arctanh \left (a x \right )}{5}+\frac {a^{3} x^{8}}{72}-\frac {11 x^{6} a}{378}+\frac {2 x^{4}}{315 a}+\frac {4 x^{2}}{315 a^{3}}+\frac {4 \ln \left (a x -1\right )}{315 a^{5}}+\frac {4 \ln \left (a x +1\right )}{315 a^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [A] time = 0.30, size = 89, normalized size = 0.93 \[ \frac {1}{7560} \, a {\left (\frac {105 \, a^{6} x^{8} - 220 \, a^{4} x^{6} + 48 \, a^{2} x^{4} + 96 \, x^{2}}{a^{4}} + \frac {96 \, \log \left (a x + 1\right )}{a^{6}} + \frac {96 \, \log \left (a x - 1\right )}{a^{6}}\right )} + \frac {1}{315} \, {\left (35 \, a^{4} x^{9} - 90 \, a^{2} x^{7} + 63 \, x^{5}\right )} \operatorname {artanh}\left (a x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [B] time = 1.01, size = 106, normalized size = 1.10 \[ \frac {4\,\ln \left (a^2\,x^2-1\right )}{315\,a^5}-\frac {11\,a\,x^6}{378}+\ln \left (a\,x+1\right )\,\left (\frac {a^4\,x^9}{18}-\frac {a^2\,x^7}{7}+\frac {x^5}{10}\right )-\ln \left (1-a\,x\right )\,\left (\frac {a^4\,x^9}{18}-\frac {a^2\,x^7}{7}+\frac {x^5}{10}\right )+\frac {2\,x^4}{315\,a}+\frac {4\,x^2}{315\,a^3}+\frac {a^3\,x^8}{72} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [A] time = 3.13, size = 100, normalized size = 1.04 \[ \begin {cases} \frac {a^{4} x^{9} \operatorname {atanh}{\left (a x \right )}}{9} + \frac {a^{3} x^{8}}{72} - \frac {2 a^{2} x^{7} \operatorname {atanh}{\left (a x \right )}}{7} - \frac {11 a x^{6}}{378} + \frac {x^{5} \operatorname {atanh}{\left (a x \right )}}{5} + \frac {2 x^{4}}{315 a} + \frac {4 x^{2}}{315 a^{3}} + \frac {8 \log {\left (x - \frac {1}{a} \right )}}{315 a^{5}} + \frac {8 \operatorname {atanh}{\left (a x \right )}}{315 a^{5}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________